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Olivana
@Olivana
January 2021
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Bonsoir, pouvez vous m aider en maths dm Svp merci
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lea006
Bonsoir,
1/On calcule BC:
Sin(angle ACB) = AB/BC
Sin (30º) = 9/BC
BC = 9 / Sin (30º)
BC= 18 cm
2/On calcule l’angle CBD
Cos (angle CBD) = BC/CD
Cos ( CBD) = 7/18
CBD = arc Cos (7/18)
A l’aide de la calculatrice on obtient
CBD= 67,1º à peu près
1 votes
Thanks 1
Olivana
Merci pour ton aide
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Lista de comentários
1/On calcule BC:
Sin(angle ACB) = AB/BC
Sin (30º) = 9/BC
BC = 9 / Sin (30º)
BC= 18 cm
2/On calcule l’angle CBD
Cos (angle CBD) = BC/CD
Cos ( CBD) = 7/18
CBD = arc Cos (7/18)
A l’aide de la calculatrice on obtient
CBD= 67,1º à peu près