Bonsoir
La loi d'Ohm s'applique
U(volts) = R(ohms)× I (ampères )
Du tableau, on tire
6 = R × 0,25 (250 mA = 0,25 A )
R = 6/0,25
R = 24 ohms
Ensuite 1ere colonne
Si I = 75 mA = 0,075 A
U = 24 × 0,075 = 1,8 V
2eme colonne
U =4 V
4 = 24 × I
I = 4/24 = 0, 167 A = 167 mA
Dernière colonne
U = 12 V
12 = 24 × I
I = 12/24 = 0,5 A = 500 mA
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Bonsoir
La loi d'Ohm s'applique
U(volts) = R(ohms)× I (ampères )
Du tableau, on tire
6 = R × 0,25 (250 mA = 0,25 A )
R = 6/0,25
R = 24 ohms
Ensuite 1ere colonne
Si I = 75 mA = 0,075 A
U = 24 × 0,075 = 1,8 V
2eme colonne
U =4 V
4 = 24 × I
I = 4/24 = 0, 167 A = 167 mA
Dernière colonne
U = 12 V
12 = 24 × I
I = 12/24 = 0,5 A = 500 mA