Bonjour,
2) Pythagore : CD² = AC²-AD² = 5²-3² = 16
donc : CD = √16 = 4 cm
3) aire ABC = (AB × CD) ÷ 2 = (10 × 4) ÷ 2 = 20 cm²
4) Pythagore : BC² = BD²+DC² = 7²+4² = 65
donc : BC = √65
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Bonjour,
2) Pythagore : CD² = AC²-AD² = 5²-3² = 16
donc : CD = √16 = 4 cm
3) aire ABC = (AB × CD) ÷ 2 = (10 × 4) ÷ 2 = 20 cm²
4) Pythagore : BC² = BD²+DC² = 7²+4² = 65
donc : BC = √65