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Alinemiaouu
@Alinemiaouu
January 2021
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Bonsoir, pouvez vous m'aider sur cet exercice de mathématiques sur lequel je bloque svp ? Merci d'avance !
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anylor
Bonjour
a)
aire triangle CDE
=base × hauteur /2
=DC × x /2
=4 × x /2
=2x
aire triangle AEB
=base × hauteur /2
hauteur issue de E dans le triangle AEB = 4-x
=AB × (4-x) / 2
=(4 × (4-x)) / 2
=(16-4x)/2
=8-2x
aire jaune
=2x+8-2x
=8
b)
aire carré ABCD
=4×4 = 16
donc aire jaune est égale à la moitié de l'aire du carré ABCD
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a)
aire triangle CDE
=base × hauteur /2
=DC × x /2
=4 × x /2
=2x
aire triangle AEB
=base × hauteur /2
hauteur issue de E dans le triangle AEB = 4-x
=AB × (4-x) / 2
=(4 × (4-x)) / 2
=(16-4x)/2
=8-2x
aire jaune
=2x+8-2x
=8
b)
aire carré ABCD
=4×4 = 16
donc aire jaune est égale à la moitié de l'aire du carré ABCD