January 2021 0 69 Report
Bonsoir, pouvez vous m'aider svp, merci d'avance 1) Calculer A, B, C et D avec a = 0,2 et b=0,3.

A = 2[2 - (4 + a)(3 - b)] + 5(4a - 2)(2b + 3)
B=2-[3-2(a-4)(5+b)]+ (2 - 3a)(5 - b)
C = 4 - 5a[2 - (3b + 3)] - 6(3b - a)
D = 7 - 2(3 - 2a)(4 - 2b) - 2[3 - 2(3 - a)(b + 1)]
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