Bonjour,
Question 1 :
f(x) = x² + 1
f'(x) = 2x
Question 2 :
f(2) = 2² + 1 = 4 + 1 = 5
f'(2) = 2 × 2 = 4
y = f'(a)(x - a) + f(a)
⇔ 4(x - 2) + 5
⇔ 4x - 8 + 5
⇔ 4x - 3
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Bonjour,
Question 1 :
f(x) = x² + 1
f'(x) = 2x
Question 2 :
f(2) = 2² + 1 = 4 + 1 = 5
f'(2) = 2 × 2 = 4
y = f'(a)(x - a) + f(a)
⇔ 4(x - 2) + 5
⇔ 4x - 8 + 5
⇔ 4x - 3