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Knounouze
@Knounouze
May 2019
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Bonsoir , qui peut m’aider à faire cet exercice , je dois factoriser cette expression , merci d’avance
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On repère immédiatement un facteur commun qui est (3x-5)
(3x-5)² - 3(2x+7)(3x-5)
= (3x-5)(3x-5) - 3(2x+7)(3x-5)
= (3x-5)[(3x-5)-3(2x+7)]
= (3x-5)(3x-6x-5-21)
= (3x-5)(-3x-26)
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Thanks 1
loulakar
Verified answer
Bonsoir,
(3x - 5)^2 - 3(2x + 7)(3x - 5) =
(3x - 5)(3x - 5 - 3(2x + 7)) =
(3x - 5)(3x - 5 - 6x - 21) =
(3x - 5)(-3x - 26)
0 votes
Thanks 1
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Verified answer
On repère immédiatement un facteur commun qui est (3x-5)(3x-5)² - 3(2x+7)(3x-5)
= (3x-5)(3x-5) - 3(2x+7)(3x-5)
= (3x-5)[(3x-5)-3(2x+7)]
= (3x-5)(3x-6x-5-21)
= (3x-5)(-3x-26)
Verified answer
Bonsoir,(3x - 5)^2 - 3(2x + 7)(3x - 5) =
(3x - 5)(3x - 5 - 3(2x + 7)) =
(3x - 5)(3x - 5 - 6x - 21) =
(3x - 5)(-3x - 26)