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inesalg16
@inesalg16
June 2021
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Bonsoir svp j’ai besoin d’aide exercice 3
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ProfdeMaths1
Verified answer
1) p(A)=200/300=
2/3
2) p=p(A∩D)+p(B∩D)=2/3*3/100+1/3*1/100=
7/300
3) p(A∪D)=(6+1+194)/300=
201/300
4) p(A∩D)=200/300*3/100=
1/50
1 votes
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Verified answer
1) p(A)=200/300=2/32) p=p(A∩D)+p(B∩D)=2/3*3/100+1/3*1/100=7/300
3) p(A∪D)=(6+1+194)/300=201/300
4) p(A∩D)=200/300*3/100=1/50