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Nouhaila43
@Nouhaila43
May 2019
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Bonsoir svp j'ai besoin d'aide. la question 5 a) la parité
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greencalogero
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Bonjour,Soit la fonction h définit par: h(x)=xIxI-4x
5)a) Pour étudier la parité de h(x), nous allons calculer h(-x):h(-x)=(-x)I-xI-4(-x)h(-x)=-xIxI+4xh(-x)=-(xIxI-4x)
h(-x)=-h(x)
La fonction h est donc impaire.
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Bonjour,Soit la fonction h définit par: h(x)=xIxI-4x5)a) Pour étudier la parité de h(x), nous allons calculer h(-x):h(-x)=(-x)I-xI-4(-x)h(-x)=-xIxI+4xh(-x)=-(xIxI-4x)h(-x)=-h(x)La fonction h est donc impaire.