Verified answer

C = (2y+1)(y+3) = 2y² +6y+y+3 = 2y²+7y+3

D = (y-5)(y-2) = y²-7y+10

Réponse :

Explications étape par étape

C= (2y × y) + ( 2y × 3) + (1 × y) + (1 × 3)  

C= 2y² + 6y + y + 3

C= 2y² + 7y + 3

D= ( y × y) + (y × (-2) + (-5 × y) + (-5 × (-2)

D= y² - 2y -5y + 10

D= y² - 7y + 10