Bonsoir
A (x) = | x - 3 ) | - [ x + 5 |
si | x - 3 | ≥ 0 ⇔ x - 3 ≥ 0 ⇔ x ≥ 3
si | x - 3 |≤ 0 ⇔ x - 3 ≤ 0 ⇔ x ≤ 3
Si | x + 5 | ≥ 0 ⇔ x + 5 ≥ 0 ⇔ x ≥ - 5
Si | x + 5 | ≤ 0 ⇔ x + 5 ≤ 0 ⇔ x ≤ - 5
x - ∞ - 5 3 + ∞
| x- 3 | - x + 3 - x + 3 0 x - 3
| x + 5 | - x- 5 0 x + 5 x + 5
| x - 3 | - |x + 5| = ( - x + 3 ) - ( - x - 5 ) = - x + 3 + x + 5 = 8
| x -3 | - |x + 5 | = ( - x + 3 ) - ( x + 5 ) = - x + 3 - x - 5 = - 2 x - 2 ⇔ x = - 1
S{ - 1 ; 8 }
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Bonsoir
A (x) = | x - 3 ) | - [ x + 5 |
si | x - 3 | ≥ 0 ⇔ x - 3 ≥ 0 ⇔ x ≥ 3
si | x - 3 |≤ 0 ⇔ x - 3 ≤ 0 ⇔ x ≤ 3
Si | x + 5 | ≥ 0 ⇔ x + 5 ≥ 0 ⇔ x ≥ - 5
Si | x + 5 | ≤ 0 ⇔ x + 5 ≤ 0 ⇔ x ≤ - 5
x - ∞ - 5 3 + ∞
| x- 3 | - x + 3 - x + 3 0 x - 3
| x + 5 | - x- 5 0 x + 5 x + 5
| x - 3 | - |x + 5| = ( - x + 3 ) - ( - x - 5 ) = - x + 3 + x + 5 = 8
| x -3 | - |x + 5 | = ( - x + 3 ) - ( x + 5 ) = - x + 3 - x - 5 = - 2 x - 2 ⇔ x = - 1
S{ - 1 ; 8 }