[tex]VA=\frac{K.Q}{dQA} \\VA= \frac{9.10x^{9} *15*10x^{6} }{5}\\VA= \frac{1,3*10x^{11}}{5} \\VA= 2,6*10x^{10} \\\\\\VB=\frac{K.Q}{dQB} \\VB= \frac{9.10x^{9} *15*10x^{6} }{10}\\VB= \frac{1,3*10x^{11}}{10} \\VB= 1,3*10x^{10} \\\\\\\\U=VA-VB\\U= 2,6*10x^{10} - 1,3*10x^{10}\\ U= 1,3*10x^{10}[/tex]
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[tex]VA=\frac{K.Q}{dQA} \\VA= \frac{9.10x^{9} *15*10x^{6} }{5}\\VA= \frac{1,3*10x^{11}}{5} \\VA= 2,6*10x^{10} \\\\\\VB=\frac{K.Q}{dQB} \\VB= \frac{9.10x^{9} *15*10x^{6} }{10}\\VB= \frac{1,3*10x^{11}}{10} \\VB= 1,3*10x^{10} \\\\\\\\U=VA-VB\\U= 2,6*10x^{10} - 1,3*10x^{10}\\ U= 1,3*10x^{10}[/tex]
Acredito que seja essa a resposta