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lol1421
@lol1421
June 2021
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c est le 33 svp c est pour demain
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lekingteck75
BFA est un triangle rectangle en F
par relation de trigonométrie
sin A = BF/BA
sin 57 =BF/6
BF= 6*sin 57≈5.03
or
cos B =BF/BA
cos B =( 6*sin(57))/6
cos B≈0.84
ARCcos B=32.9°
donc L'angle ABF=32.9°
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Lista de comentários
par relation de trigonométrie
sin A = BF/BA
sin 57 =BF/6
BF= 6*sin 57≈5.03
or
cos B =BF/BA
cos B =( 6*sin(57))/6
cos B≈0.84
ARCcos B=32.9°
donc L'angle ABF=32.9°