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ornella3
@ornella3
January 2021
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C le À C’est sur le théorème de Pythagore pouvez-vous m’aider s’il vous plaît merci
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taalbabachir
Calculer les longueurs AB, AC et BC
A(3 ; 7) B(- 3 ; 1) C(1 ; - 3)
AB² = (- 3 - 3)² + (1 - 7)² = (- 6)² + (- 6)² = 36 + 36 = 72
BC² = (1 - (- 3))² + (- 3 - 1)² = (1 + 3)² + (- 4)² = 4² + (- 4)² = 16 + 16 = 32
AB² + BC² = 72 + 32 = 104
AC² = (1 - 3)² + ( - 3 - 7)² = (- 2)² + (- 10)² = 4 + 100 = 104
⇒ donc le triangle ABC est rectangle en B
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A(3 ; 7) B(- 3 ; 1) C(1 ; - 3)
AB² = (- 3 - 3)² + (1 - 7)² = (- 6)² + (- 6)² = 36 + 36 = 72
BC² = (1 - (- 3))² + (- 3 - 1)² = (1 + 3)² + (- 4)² = 4² + (- 4)² = 16 + 16 = 32
AB² + BC² = 72 + 32 = 104
AC² = (1 - 3)² + ( - 3 - 7)² = (- 2)² + (- 10)² = 4 + 100 = 104
⇒ donc le triangle ABC est rectangle en B