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raayamane
@raayamane
April 2022
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Calcule a razão de uma P.G. de seis termos, cujos extremos são 3 e 96.
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carolollero
PG(a1,a2,a3,a4,a5,a6) =(3,a2,a3,a4,a5,96)
Usando a fórmula do termo geral:
an=a1.q^(n-1)
Assim:
a6=a1.q^5
96= 3.q^5
q^5 = 32
q^5 =2^5
q=5
RAZÃO: 5
7 votes
Thanks 9
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Lista de comentários
Usando a fórmula do termo geral:
an=a1.q^(n-1)
Assim:
a6=a1.q^5
96= 3.q^5
q^5 = 32
q^5 =2^5
q=5
RAZÃO: 5