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betamenezes3
@betamenezes3
March 2022
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Calcule a soma dos quinzes termos da P.A (-45,-41,-37,-33...)
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Verified answer
A15 = a1 + (n - 1). r
A15 = -45 + (15 - 1)4
A15 = -45 +60 - 4
A15 = -49 + 60
A15 = 11
==================
S15 =
(-45 + 11) . 15
2
S15 =
-34 . 15
2
S15 = - 510 / 2
S15 = - 255
Resp: a soma dos 15 termos (S15) = - 255
1 votes
Thanks 3
Verkylen
Verified answer
P.A.=(-45, -41, -37, -33,...)
r = a2 - a1
r = -41 - (-45)
r = -41 + 45
r = 4
a15 = a1 + 14r
a15 = -45 + 14(4)
a15 = -45 + 56
a15 = 11
S15 = 15(a1 + a15)/2
S15 = 15(-45 + 11)/2
S15 = 15(-34)/2
S15 = 15(-17)
S15 = -255
0 votes
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Verified answer
A15 = a1 + (n - 1). rA15 = -45 + (15 - 1)4
A15 = -45 +60 - 4
A15 = -49 + 60
A15 = 11
==================
S15 = (-45 + 11) . 15
2
S15 = -34 . 15
2
S15 = - 510 / 2
S15 = - 255
Resp: a soma dos 15 termos (S15) = - 255
Verified answer
P.A.=(-45, -41, -37, -33,...)r = a2 - a1
r = -41 - (-45)
r = -41 + 45
r = 4
a15 = a1 + 14r
a15 = -45 + 14(4)
a15 = -45 + 56
a15 = 11
S15 = 15(a1 + a15)/2
S15 = 15(-45 + 11)/2
S15 = 15(-34)/2
S15 = 15(-17)
S15 = -255