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louidta
@louidta
March 2022
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calcule a soma dos quarenta primeiros termos da PA (4,10,16,22,...)
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EmilyVeloso2
Primeiro calculando a40 a40=4+39.5=199
Calculando S40:
2)a22=a1+21.r80=-4+21r84=21rr=84/21r=4
3)
Se a1+a5=-14 -> a1+a1+4r=-14 -> 2a1 +4r=-14 (1)Se a1+a10=1 -> a1+a1+9r=1 -> 2a1+9r=1 (2) Subtraindo as equações
(2)-(1) = 5r=15 -> r=3
De (2): 2a1+9r=1 -> 2a1+27=1 -> 2a1=-26 -> a1=-13
Agora calculando a15=a1+14r = -13+14.3=
29
Finalmente calculando S15:
Espero te ajudado !!!!!
1 votes
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louidta
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Calculando S40: 2)a22=a1+21.r80=-4+21r84=21rr=84/21r=4
3) Se a1+a5=-14 -> a1+a1+4r=-14 -> 2a1 +4r=-14 (1)Se a1+a10=1 -> a1+a1+9r=1 -> 2a1+9r=1 (2) Subtraindo as equações (2)-(1) = 5r=15 -> r=3 De (2): 2a1+9r=1 -> 2a1+27=1 -> 2a1=-26 -> a1=-13 Agora calculando a15=a1+14r = -13+14.3= 29 Finalmente calculando S15: Espero te ajudado !!!!!