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ljessiane
@ljessiane
April 2022
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Calcule o produto:
(3+2i)²
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Jhanaina
(3+2i)²
(3+2i). (3+2i)
9+6i+6i+4i²
9+12i+4i²
4i²₊12i+9₌0
Δ₌b²-4.a.c
Δ₌12²-4.4.9
Δ₌0
Δ₌-b±Raiz Δ/2.a
Δ₌-12±Raiz0/2.4
Δ₌ -1,5
TIRANDO A PROVA REAL
4.(-1,5)²+12(-1,5)+9₌0
9-18+9₌0
18-18 igual a zero
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ljessiane
April 2022 | 0 Respostas
Calcule os produtos a seguir A) 2i.(-2+3i)
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(3+2i). (3+2i)
9+6i+6i+4i²
9+12i+4i²
4i²₊12i+9₌0
Δ₌b²-4.a.c
Δ₌12²-4.4.9
Δ₌0
Δ₌-b±Raiz Δ/2.a
Δ₌-12±Raiz0/2.4
Δ₌ -1,5
TIRANDO A PROVA REAL
4.(-1,5)²+12(-1,5)+9₌0
9-18+9₌0
18-18 igual a zero