Resposta:

Triângulo retângulo:

hipotenusa = 2,3m

cateto₁ = base = x

cateto₂ = altura = 1,8m

Fómula:

(hipotenusa)² = (altura)² + (base)²

[tex](2,3m)^{2} =(1,8m)^{2} +xm^{2} \\ \\ xm^{2} =(2,3m)^{2} -(1,8m)^{2}\\ \\ xm^{2} =5,29m^{2} -3,24m^{2} \\ \\ x^{2} =2,05m^{2} \\ \\ x=\sqrt{2,05m^{2} } \\ \\ x=1,43m[/tex]