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oscarjanovichj
@oscarjanovichj
June 2023
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Calcule o valor de X nos quadrilátero abaixo:
Me ajude por favor é para amanhã
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Ar0n
A soma dos ângulos de um quadrilátero é igual a 360°
a)
125+110+74+x=360
304+x=360
x=360-304
x=56°
b)
120+120+x+x=360
240+2x=360
2x=360-240
2x=120
x=120/2
x=60°
c)(ângulo reto é igual a 90°)
90+80+75+x=360
245+x=360
x=360-245
x=115°
d)
(x+60)+(x+40)+(x+20)+x=360
4x+120=360
4x=360-120
4x=240
x=240/4
x=60°
1 votes
Thanks 1
oscarjanovichj
muito obrigado mesmo
Ar0n
De nada! ;)
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a)
125+110+74+x=360
304+x=360
x=360-304
x=56°
b)
120+120+x+x=360
240+2x=360
2x=360-240
2x=120
x=120/2
x=60°
c)(ângulo reto é igual a 90°)
90+80+75+x=360
245+x=360
x=360-245
x=115°
d)
(x+60)+(x+40)+(x+20)+x=360
4x+120=360
4x=360-120
4x=240
x=240/4
x=60°