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Laryssa53
@Laryssa53
March 2022
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Calcule o valor de x nos triângulos retângulos.
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PaulaValadao
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Fazer por pitagóras.
h^2= a^2+b^2
h^2= (raiz de 2) ^2 +( raiz de 3)^2
corta raiz com o quadrado
h^2= 2+3
h= raiz de 5
(3*raiz de5 ) ^2 = 6^2 +x^2
9*5= 36+x^2
x^2= 45-36
x^2= 9
x=3
2x^2= (3*raiz de 3)^2 + x^2
4x^2= 9*3 + x^2
4x^2 = 27 + x^2
3x^2 =27
x^2= 9
x=3
(x+5)^2 = (x+3)^2 + 6^2 faz o chiveirinho
x^2 + 5x +5x +25= (x^2 + 3x+ 3x +9) +36
podemos cortar o x^2
4x - 20 = 0
x= 20/4
x= 5
159 votes
Thanks 301
PaulaValadao
o h aí do primeiro é o x, esqueci de colocar de acordo
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Lista de comentários
Verified answer
Fazer por pitagóras.h^2= a^2+b^2
h^2= (raiz de 2) ^2 +( raiz de 3)^2
corta raiz com o quadrado
h^2= 2+3
h= raiz de 5
(3*raiz de5 ) ^2 = 6^2 +x^2
9*5= 36+x^2
x^2= 45-36
x^2= 9
x=3
2x^2= (3*raiz de 3)^2 + x^2
4x^2= 9*3 + x^2
4x^2 = 27 + x^2
3x^2 =27
x^2= 9
x=3
(x+5)^2 = (x+3)^2 + 6^2 faz o chiveirinho
x^2 + 5x +5x +25= (x^2 + 3x+ 3x +9) +36
podemos cortar o x^2
4x - 20 = 0
x= 20/4
x= 5