Articles
Register
Sign In
Search
Laryssa53
@Laryssa53
March 2022
1
43
Report
Calcule o valor de x nos triângulos retângulos.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
PaulaValadao
Verified answer
Fazer por pitagóras.
h^2= a^2+b^2
h^2= (raiz de 2) ^2 +( raiz de 3)^2
corta raiz com o quadrado
h^2= 2+3
h= raiz de 5
(3*raiz de5 ) ^2 = 6^2 +x^2
9*5= 36+x^2
x^2= 45-36
x^2= 9
x=3
2x^2= (3*raiz de 3)^2 + x^2
4x^2= 9*3 + x^2
4x^2 = 27 + x^2
3x^2 =27
x^2= 9
x=3
(x+5)^2 = (x+3)^2 + 6^2 faz o chiveirinho
x^2 + 5x +5x +25= (x^2 + 3x+ 3x +9) +36
podemos cortar o x^2
4x - 20 = 0
x= 20/4
x= 5
159 votes
Thanks 301
PaulaValadao
o h aí do primeiro é o x, esqueci de colocar de acordo
More Questions From This User
See All
Laryssa53
March 2022 | 0 Respostas
Responda
Laryssa53
March 2022 | 0 Respostas
Responda
Laryssa53
October 2020 | 0 Respostas
Responda
Laryssa53
October 2020 | 0 Respostas
Responda
Laryssa53
October 2020 | 0 Respostas
Responda
Laryssa53
October 2020 | 0 Respostas
Responda
×
Report "Calcule o valor de x nos triângulos retângulos.... Pergunta de ideia de Laryssa53"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Fazer por pitagóras.h^2= a^2+b^2
h^2= (raiz de 2) ^2 +( raiz de 3)^2
corta raiz com o quadrado
h^2= 2+3
h= raiz de 5
(3*raiz de5 ) ^2 = 6^2 +x^2
9*5= 36+x^2
x^2= 45-36
x^2= 9
x=3
2x^2= (3*raiz de 3)^2 + x^2
4x^2= 9*3 + x^2
4x^2 = 27 + x^2
3x^2 =27
x^2= 9
x=3
(x+5)^2 = (x+3)^2 + 6^2 faz o chiveirinho
x^2 + 5x +5x +25= (x^2 + 3x+ 3x +9) +36
podemos cortar o x^2
4x - 20 = 0
x= 20/4
x= 5