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Andressa55
@Andressa55
October 2020
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Calcule:
a) i^25
b) i^2003
c) i^28
d) i^17 + 3i^288 - 21i^182
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3478elc
Verified answer
a) i^25 = i^1 ====>
i
b) i^2003 = i^3 ==>
- i
c) i^28 = i ^0 ==>
1
d) i^17 + 3i^288 - 21i^95 + i^30
==> i^1+ 3.i^0 - 21i^3 + i^2==> i + 3 - 2(-i) +(-1)
==> i + 3 + 2i -1) ==>
2 + 3i
e) 4.(3+2i^43)-6.(1+i^603)+21i^182
4.(3+2i^3)-6.(1+i^3)+21i^2
12 + 8i^3- 6 - 6i^3 + 21i^2
12 - 8i - 6 + 6i - 21
- 15 - 2i
25 4 28 4 17 4 288 4 95 4
-24
6
-28
7
-16
4
-288
72
-15
23 1 0 1 0 15
-12
3
2 votes
Thanks 1
Andressa55
desculpa a ''d'' eu coloquei errada, então:
Andressa55
d) i^17 +3i^288 -2i^95 +i^30 tenha a ''e'' tbm: e) 4.(3+2i^43)-6.(1+i^603)+21i^182
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Verified answer
a) i^25 = i^1 ====> i
b) i^2003 = i^3 ==> - i
c) i^28 = i ^0 ==> 1
d) i^17 + 3i^288 - 21i^95 + i^30 ==> i^1+ 3.i^0 - 21i^3 + i^2==> i + 3 - 2(-i) +(-1)
==> i + 3 + 2i -1) ==> 2 + 3i
e) 4.(3+2i^43)-6.(1+i^603)+21i^182
4.(3+2i^3)-6.(1+i^3)+21i^2
12 + 8i^3- 6 - 6i^3 + 21i^2
12 - 8i - 6 + 6i - 21
- 15 - 2i
25 4 28 4 17 4 288 4 95 4
-24 6 -28 7 -16 4 -288 72 -15 23 1 0 1 0 15 -12
3