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TheoBLLG
@TheoBLLG
May 2019
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Caluler en détaillant les étapes et en remplacant x par -1 sur 4. (5x - 2)² - (x - 7) (5x - 2)
Merci de m'aider SVP
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maudmarine
Verified answer
Bonsoir,
(5x - 2)² - (x - 7) (5x - 2)
= (5 (-1/4) - 2)² - (- 1/4 - 7) (5 (- 1/4) - 2)
= (- 5/4 - 2)² - (- 1/4 - 28/4) (- 5/4 - 2)
= (- 5/4 - 8/4)² - (- 29/4) (- 5/4 - 8/4)
= (- 13/4)² - (- 29/4) (- 13/4)
= (- 13²/4²) - 377/16
= 169/16 - 377/16
= - 208/16
= 16 x (- 13) / 16 x 1
= - 13
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Verified answer
Bonsoir,(5x - 2)² - (x - 7) (5x - 2)
= (5 (-1/4) - 2)² - (- 1/4 - 7) (5 (- 1/4) - 2)
= (- 5/4 - 2)² - (- 1/4 - 28/4) (- 5/4 - 2)
= (- 5/4 - 8/4)² - (- 29/4) (- 5/4 - 8/4)
= (- 13/4)² - (- 29/4) (- 13/4)
= (- 13²/4²) - 377/16
= 169/16 - 377/16
= - 208/16
= 16 x (- 13) / 16 x 1
= - 13