December 2020 0 110 Report
Cc est ce que quelqu’un peut m'aidez svp Þ (8 x 1) + (2 x 0,1) + (4 x 0,01) + (7 x 0,001) = 8,247
(4 x 1) + (6 x 0,1) = …….
(5 x 1) + (2 x 0,1) + (4 x 0,01) = ……...
(5 x 1) + ( 8 x 0,1 ) + ( 6 x 0,01 ) + ( 7 x 0,001) = ……….
( ... x 1 ) + ( 5 x …..... ) = 4,05
( ... x 10 ) + ( 3 x ….... ) + ( …... x ….. ) = 60,306
( ... x ... ) + ( ….. x ..... ) + ( ….... x ……. ) + ( …..... + ….... ) = 7,368
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