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Eliias
@Eliias
April 2019
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Ce serait gentil de m'aider : On considère l'expression F=(5-6x)(4x-1)+16x²-8x+1et on me demande de résoudre l'équation si F=0
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manaine31
F= (5-6x)(4x-1) +(4x-1) au carre
F=(4x-1)[(5-6x)+(4x-1)]
F=(4x-1)(5-6x+4x-1)
F=(4x-1)(2x+4)=0
4x-1=0 ou. 2x+4=0
4x=1 2x= -4
x=1/4 x=-4/2
x=o,25 x= -2
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F=(4x-1)[(5-6x)+(4x-1)]
F=(4x-1)(5-6x+4x-1)
F=(4x-1)(2x+4)=0
4x-1=0 ou. 2x+4=0
4x=1 2x= -4
x=1/4 x=-4/2
x=o,25 x= -2