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SpyFox
@SpyFox
January 2021
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Merci de m'aider svp je galère :-/
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corinnemattonchips59
Bonjour
a)
volume d'un cone=
v = π x r² x h /3
v = π x 1,20² x 1,60 /3
v= π x 1,44 x 1,60 /3
v= π x 2,304 /3
v= 2,413 m³
b) 2,413 + 10,857 = 13,27 m³
13,27 m³ = 13270 l
la contenance totale du silo est de 13270 litres
2a)
SO/SA= 1,20/1,60= 0,75
0,75= 3/4
le coefficient de réduction est de 3/4
b) V x k³
2,413 x 0,75³
2,413 x 0,4218
v= 1,0179
arrondi = 1,018m³ environ
partie 2
HC= 2,40 + 1,60
HC= 4
HB/HC=1,60/4= 0,4
HM/HN= 0,8/2= 0,4
HB/HC=HM/HN
donc (BM) // (CN)
les échelles sont donc parallèles
1 votes
Thanks 1
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Svp aidez-moi c'est pour demain !!!!!!
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Bonjour pouvez-vous m'aider svp c'est tout simple mais je n'y arrive pas !!
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a)
volume d'un cone=
v = π x r² x h /3
v = π x 1,20² x 1,60 /3
v= π x 1,44 x 1,60 /3
v= π x 2,304 /3
v= 2,413 m³
b) 2,413 + 10,857 = 13,27 m³
13,27 m³ = 13270 l
la contenance totale du silo est de 13270 litres
2a)
SO/SA= 1,20/1,60= 0,75
0,75= 3/4
le coefficient de réduction est de 3/4
b) V x k³
2,413 x 0,75³
2,413 x 0,4218
v= 1,0179
arrondi = 1,018m³ environ
partie 2
HC= 2,40 + 1,60
HC= 4
HB/HC=1,60/4= 0,4
HM/HN= 0,8/2= 0,4
HB/HC=HM/HN
donc (BM) // (CN)
les échelles sont donc parallèles