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Amalf
@Amalf
April 2019
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C'est l'exercice 17 et le 33, merci de m'aidez aux plus vite, svp
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nathalienouts
ex 17
Théorème de Pythagore
PA² = CP² +CA²
PA = √(CP²+CA²)
PA = √(4,5²+6²)
PA = 7,5 cm
ex 23
Théorème de Pyrhagore
BC² = 60²+150²
BC = √(60²+150²)
BC = 30√29 cm
or AB = 2BC
AB = 60√29
Théorème de Pythagore
AB² = 120² + P²
P² = AB²-120²
P = √(AB²-120²)
P = √((60√29)²-120²)
P = 60√33
P = 344,7 cm
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Théorème de Pythagore
PA² = CP² +CA²
PA = √(CP²+CA²)
PA = √(4,5²+6²)
PA = 7,5 cm
ex 23
Théorème de Pyrhagore
BC² = 60²+150²
BC = √(60²+150²)
BC = 30√29 cm
or AB = 2BC
AB = 60√29
Théorème de Pythagore
AB² = 120² + P²
P² = AB²-120²
P = √(AB²-120²)
P = √((60√29)²-120²)
P = 60√33
P = 344,7 cm