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Rider2
@Rider2
May 2019
1
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C'est pour demain !
on considère l'expression :
D = (2x + 3)² + (x - 5)(2x + 3)
a) Développer et réduire l'expression D
b) Factoriser l'expression D
c) Résoudre l'équation : D = 0
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Bonjour
a)
D = (2x + 3)² + (x - 5)(2x + 3)
D= 4x^2 +12x +9 + 2x^2+ 3x -10x -15
D= 6x^2 +5x -6
b)
D = (2x + 3)² + (x - 5)(2x + 3)
D= (2x + 3) (2x+3) + (x-5)(2x+3)
D= (2x+3) ((2x+3)+(x-5))
D= (2x+3) (2x+3+x-5)
D= (2x+3) (3x-2)
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rider2
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January 2021 | 0 Respostas
c'est pour demain merci d'avance
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Rider2
May 2019 | 0 Respostas
Bonjour, j'ai ces 2 exo a faire pr demain et je ne comprend rien. merci du coup de main !
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Rider2
May 2019 | 0 Respostas
Je ne trouve pas la longueur du segment ms, merci d'avance !
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Rider2
May 2019 | 0 Respostas
Je ne sais pas comment faire, help
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a)
D = (2x + 3)² + (x - 5)(2x + 3)
D= 4x^2 +12x +9 + 2x^2+ 3x -10x -15
D= 6x^2 +5x -6
b)
D = (2x + 3)² + (x - 5)(2x + 3)
D= (2x + 3) (2x+3) + (x-5)(2x+3)
D= (2x+3) ((2x+3)+(x-5))
D= (2x+3) (2x+3+x-5)
D= (2x+3) (3x-2)