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Resposta:

1)

[tex] {(0.2)}^{3} + {(0.16)}^{2} = \\ \frac{2}{10} . \frac{2}{10} . \frac{2}{10} + \frac{16}{100} . \frac{16}{100} = \\ \frac{2.2.2}{10.10.10} + \frac{16.16}{100.100} = \\ \frac{8}{1000} + \frac{256}{10000} = \\ \frac{80}{10000} + \frac{256}{10000} = \\ \frac{336}{10000} = 0.0336[/tex]

2)

[4²+(5-3)²]: (9-7)²

[4²+2²] : 2²

[16+4] : 4

20 : 4

5

3) Se A=2x+4y+5

B=2x+2y-3

C=4x-y+4

A+B+C = (2x+4y+5) + (2x+2y-3) + (4x-y+4)

A+B+C = 2x + 2x + 4x + 4y +2y - y + 5 - 3 + 4

A+B+C = 8x + 4y +2y - y + 5 - 3 + 4

A+B+C = 8x + 5y + 5 - 3 + 4

A+B+C = 8x + 5y + 6

Resposta:

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