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Leatitiastewart
@Leatitiastewart
April 2019
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Bonjour,
Pourriez vous m'aider pour ces équations :
1) (3x+1)² = 16(x-2)²
2) 3/x = 5/x-1
J'utilise le / comme barre de fraction c'est donc 3 sur x et 5 sur x-1
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Commentaires (1)
1) (3x+1)² = 16(x-2)²
3x+1=4(x-2) ou 3x+1=-4(x-2)
x=9 ou x=1
2) 3/x = 5/(x-1)
3(x-1)=5x
x=-3/2
2 votes
Thanks 1
leatitiastewart
Merci beaucoup !
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3x+1=4(x-2) ou 3x+1=-4(x-2)
x=9 ou x=1
2) 3/x = 5/(x-1)
3(x-1)=5x
x=-3/2