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Mrvalentindu622
@Mrvalentindu622
April 2019
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Comment factoriser :
(4x-6)²-(2x-4)²
Merci :)
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nathalienouts
Il faut utiliser l'identité remarquable a²-b² = (a+b)(a-b)
(4x-6)²-(2x-4)²
= (4x-6+2x-4)(4x-6-2x+4)
= (6x-10)(2x-2)
3 votes
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nutella62
(4x-6)²-(2x-4)²
=(4x²-2*4x*6+6²)-(2x²-2*2x*4+4²)
=4x²-48x+36-2x²-16x+16
=2x²-64x+52
J'espère t'avoir aidé !
2 votes
Thanks 0
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(4x-6)²-(2x-4)²
= (4x-6+2x-4)(4x-6-2x+4)
= (6x-10)(2x-2)
=(4x²-2*4x*6+6²)-(2x²-2*2x*4+4²)
=4x²-48x+36-2x²-16x+16
=2x²-64x+52
J'espère t'avoir aidé !