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Jacque
@Jacque
April 2019
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Comment on calcule la valeur approchée de 201.06192982974676 à 1 cm² près par excès ?
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ilona150
Tu fais la valeur au carré ² et tu divise
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DETERMINE C EM :a- log 8 na base 2 = c b- log 4 na base 2 = cc- log 13 na base 13 = c d- log 1 na base 5 = c e- log 4 na base 4 ^3 = c f- log 1 na base 5 = c
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DADOS log 2 = 0,30 e log 3 = 0,48 , DETERMINE :a- log 6 b- log 8 c- log raiz 3
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