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alessandra1002
@alessandra1002
March 2022
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Como resolver as inequações abaixo?
a) 2x - 15 < -x
b) 4 - 3x > x + 6
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mirelly2014
A) 2x - 15 < -x
2x + x < 15
3x < 15
x < 15: 3
x < 5
B) 4 - 3x > x + 6
-3x - x > 6 - 4
-4x > 2 (.-1)
4x < -2
x < -2:4
x < -0,5
2 votes
Thanks 9
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Lista de comentários
2x + x < 15
3x < 15
x < 15: 3
x < 5
B) 4 - 3x > x + 6
-3x - x > 6 - 4
-4x > 2 (.-1)
4x < -2
x < -2:4
x < -0,5