Como resolvo log 27 na base 3√3?.... Pergunta de ideia deheloizasantos

April 2022 1 25 Report

Como resolvo log 27 na base 3√3?

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GFerraz $(3\sqrt{3})^x = 27 \\ \\ (\sqrt{27})^x = 27 \\ \\ (\sqrt{3^3})^x = 3^3 \\ \\ (3^{\frac{3}{2}})^x = 3^3 \\ \\ \not3^{\frac{3x}{2}} = \not3^3 \\ \\ 3x = 3 . 2 \\ \\ 3x = 6 \\ \\ \\ \boxed{x = 2}$

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