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Danablanquet
@Danablanquet
April 2019
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Coucou g besoin de génies s'il vous plaît :)
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A.) E entre C et D ------------- 0 ≤ x ≤ 90
b.) CE = 90 - x
c.) BED est un Δ rectangle en D ,
tan DEB = DB / DE
= 35 / x
d.) NEC est un Δ rectangle en C ,
tan CEN = CN / CE
= 25 / 90 - x
e.)
CEN = DEB
tan CEN = tan DEB
25/90-x = 35/x
35 (90 - x ) = 25x
3150 - 35x = 25x
25x + 35x = 3150
60x = 3150
x = 3150/60
x = 52.5
f.)
tan DEB = 35/x
35/52.5
Alors, DEB = tan⁻¹(35/52.5) ≈ 34° = CEN
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Thanks 1
Danablanquet
merci beaucoup :)
Reem
dr ,,, Bonne chance
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Lista de comentários
b.) CE = 90 - x
c.) BED est un Δ rectangle en D ,
tan DEB = DB / DE
= 35 / x
d.) NEC est un Δ rectangle en C ,
tan CEN = CN / CE
= 25 / 90 - x
e.)
CEN = DEB
tan CEN = tan DEB
25/90-x = 35/x
35 (90 - x ) = 25x
3150 - 35x = 25x
25x + 35x = 3150
60x = 3150
x = 3150/60
x = 52.5
f.)
tan DEB = 35/x
35/52.5
Alors, DEB = tan⁻¹(35/52.5) ≈ 34° = CEN