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lise280801
@lise280801
January 2021
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de l'aide s'il vous plaît, j'ai tous réussi sauf celui là. (3x-2)*-(5x+3)*
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Ibnbatota
Il faut utiliser l'identité remarquabe a au carré - b au carré = (a-b) x (a+b)
avec a = 3x-2 et b=5x+3
donc (3x-2)-(5x+3))x [(3x-2)+(5x+3)]
-2x-5 )x (8x+1) = -16 x au carré-40x-2x-5 = -16xaucarré-42x-5
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uswii
(3x-2)² - (5x+3)²
= 3x² + 2² + 2 × 3x × -2 - 5x² + 3² + 2 × 5x × 3
= 3x² + 4 - 12x - 5x² + 9 + 30x
= -2x² + 18x + 13
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avec a = 3x-2 et b=5x+3
donc (3x-2)-(5x+3))x [(3x-2)+(5x+3)]
-2x-5 )x (8x+1) = -16 x au carré-40x-2x-5 = -16xaucarré-42x-5
= 3x² + 2² + 2 × 3x × -2 - 5x² + 3² + 2 × 5x × 3
= 3x² + 4 - 12x - 5x² + 9 + 30x
= -2x² + 18x + 13