Articles
Register
Sign In
Search
Taradu29
@Taradu29
May 2019
1
101
Report
Dérivée de x racine de x ?? J'arrive pas j'ai besoin d'aide merci d'avance
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Bernie76
Bonour,
f(x)=x√x est de la forme u*v avec :
u=x donc u'=1
v=√x donc v'=1/2√x
f '(x)=u'v+uv'=√x*x/(2√x)=x/2
0 votes
Thanks 0
Bernie76
: - )
More Questions From This User
See All
Taradu29
January 2021 | 0 Respostas
Responda
Taradu29
January 2021 | 0 Respostas
Responda
Taradu29
January 2021 | 0 Respostas
Responda
Taradu29
January 2021 | 0 Respostas
Responda
Taradu29
January 2021 | 0 Respostas
Responda
Taradu29
May 2019 | 0 Respostas
Responda
Taradu29
May 2019 | 0 Respostas
Responda
Taradu29
May 2019 | 0 Respostas
Responda
Taradu29
May 2019 | 0 Respostas
Responda
×
Report "Dérivée de x racine de x ?? J'arrive pas j'ai besoin d'aide merci d'avance.... Pergunta de ideia de Taradu29"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
f(x)=x√x est de la forme u*v avec :
u=x donc u'=1
v=√x donc v'=1/2√x
f '(x)=u'v+uv'=√x*x/(2√x)=x/2