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SophiRodrigues
@SophiRodrigues
October 2020
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Desenvolva algebricamente cada potencia:
a) (2b+3)² e b)( +7y) ²
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vitorhugodesimone
a) (2b+3)² = (2b)
² + 2.2b.3 + 3² ==> 4b² + 12b + 9
b)( +7y) ² = 49y
²
6 votes
Thanks 4
3478elc
Verified answer
A) (2b+3)²=
(2b+3)(2b+3)=
4b²+6b+6b+9=
4b²+12b+9=
Δ=b²-4ac
Δ=(12)²-4(4)(9)
Δ=144-144
Δ=0
b=(-b+-√Δ)/2a
b=(-12+-√0)/2•4
b=(-12+-0)/8
b'=-12-0/8
b'=-12/8
b'=-1,5
b"=-12+0/8
b"=-12/8
b"-1,5
S={-1,5;-1,5}
B) (7y)²=
(7y)(7y)=
49y²
7 votes
Thanks 6
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Lista de comentários
a) (2b+3)² = (2b)² + 2.2b.3 + 3² ==> 4b² + 12b + 9
b)( +7y) ² = 49y²
Verified answer
A) (2b+3)²=(2b+3)(2b+3)=
4b²+6b+6b+9=
4b²+12b+9=
Δ=b²-4ac
Δ=(12)²-4(4)(9)
Δ=144-144
Δ=0
b=(-b+-√Δ)/2a
b=(-12+-√0)/2•4
b=(-12+-0)/8
b'=-12-0/8
b'=-12/8
b'=-1,5
b"=-12+0/8
b"=-12/8
b"-1,5
S={-1,5;-1,5}
B) (7y)²=
(7y)(7y)=
49y²