bonsoir
a) x² = x ⇒ x = √x ou - √x
b) ( x + 3)² + x² = x² + 6 x + 9 + x² = 2 x² + 6 x + 9
c) ( x - 1) ( x - 2) ( x - 4) = ( x² - 2 x - x + 2 ) ( x - 4)
= ( x² - 3 x + 2 ) ( x - 4) = x ³ - 4 x² - 3 x² + 12 x + 2 x - 8 = x³ - 7 x² + 14 x - 8
d) 2 x² - 8 x + 15 = 2 ( x - 2)² + 7 oui mais forme canonique, tu as vu cela ?
e) ( x + 5) ( x - 3) = x² - 3 x + 5 x - 15 = x² + 2 x - 15
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bonsoir
a) x² = x ⇒ x = √x ou - √x
b) ( x + 3)² + x² = x² + 6 x + 9 + x² = 2 x² + 6 x + 9
c) ( x - 1) ( x - 2) ( x - 4) = ( x² - 2 x - x + 2 ) ( x - 4)
= ( x² - 3 x + 2 ) ( x - 4) = x ³ - 4 x² - 3 x² + 12 x + 2 x - 8 = x³ - 7 x² + 14 x - 8
d) 2 x² - 8 x + 15 = 2 ( x - 2)² + 7 oui mais forme canonique, tu as vu cela ?
e) ( x + 5) ( x - 3) = x² - 3 x + 5 x - 15 = x² + 2 x - 15