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dayaneeeeee
@dayaneeeeee
October 2020
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determine a area de um triangulo retangulo cuja hipotenusa mede 10cm e um cateto mede 5cm
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jonesab7
H² - c² = x, A hipotenusa h² = 10² = 100, o cateto c² = 5 = 25
hipotenusa - cateto = 100 - 25 = raiz de V 75 = 8,660
vezes ===== x 5 ¨¨¨¨¨¨¨¨¨¨¨¨ 43,30 / 2 = 21,65 ²
Resposta: 21,65 m ou cm.
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hipotenusa - cateto = 100 - 25 = raiz de V 75 = 8,660
vezes ===== x 5 ¨¨¨¨¨¨¨¨¨¨¨¨ 43,30 / 2 = 21,65 ²
Resposta: 21,65 m ou cm.