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joycemrs
@joycemrs
October 2020
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Determine a medida aproximada da altura do triângulo.
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Monteirov
Sen(45º)=
⇔ h=sen(45º)×5,6
Nota: sen(x)=
7 votes
Thanks 11
eduardofilipe
Sen45° = cateto oposto/hipotenusa
Sen45° = h / 5,6
1/2 = h / 5,6
h= 2,8 cm
8 votes
Thanks 14
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Lista de comentários
Nota: sen(x)=
Sen45° = h / 5,6
1/2 = h / 5,6
h= 2,8 cm