Resposta:
Eis as respostas solicitadas pela Tarefa:
Explicação passo a passo:
Vamos apresentar a resolução da Tarefa:
[tex]A)\:\sqrt{9}=\sqrt{3^2}=3^{\frac{2}{2}}=3^{1}=3\\\\B)\:\sqrt{16}=\sqrt{2^4}=2^{\frac{4}{2}}=2^{2}=2\cdot2=4\\\\C)\:\sqrt{25}=\sqrt{5^2}=5^{\frac{2}{2}}=5^{1}=5\\\\D)\:\sqrt{81}=\sqrt{3^4}=3^{\frac{4}{2}}=3^{2}=3\cdot3=9\\\\E)\:\sqrt{0}=0\\\\F)\:\sqrt{1}=1\\\\G)\:\sqrt{64}=\sqrt{2^6}=2^{\frac{6}{2}}=2^{3}=2\cdot2\cdot2=8\\\\H)\:\sqrt{100}=\sqrt{2^2\cdot5^2}=\sqrt{(2\cdot5)^2}=\sqrt{10^2}=10^{\frac{2}{2}}=10^{1}=10[/tex]
A) √9= 3
B)√16= 4
C)√25= 5
D)√81= 9
E)√0= 0
F)√1= 1
G)√64= 8
H)√100= 10
Encontra-se a raíz quadrada fatorando
13/06/23
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Lista de comentários
Resposta:
Eis as respostas solicitadas pela Tarefa:
Explicação passo a passo:
Vamos apresentar a resolução da Tarefa:
[tex]A)\:\sqrt{9}=\sqrt{3^2}=3^{\frac{2}{2}}=3^{1}=3\\\\B)\:\sqrt{16}=\sqrt{2^4}=2^{\frac{4}{2}}=2^{2}=2\cdot2=4\\\\C)\:\sqrt{25}=\sqrt{5^2}=5^{\frac{2}{2}}=5^{1}=5\\\\D)\:\sqrt{81}=\sqrt{3^4}=3^{\frac{4}{2}}=3^{2}=3\cdot3=9\\\\E)\:\sqrt{0}=0\\\\F)\:\sqrt{1}=1\\\\G)\:\sqrt{64}=\sqrt{2^6}=2^{\frac{6}{2}}=2^{3}=2\cdot2\cdot2=8\\\\H)\:\sqrt{100}=\sqrt{2^2\cdot5^2}=\sqrt{(2\cdot5)^2}=\sqrt{10^2}=10^{\frac{2}{2}}=10^{1}=10[/tex]
A) √9= 3
B)√16= 4
C)√25= 5
D)√81= 9
E)√0= 0
F)√1= 1
G)√64= 8
H)√100= 10
Encontra-se a raíz quadrada fatorando
❤️❤️ Ótima tarde ❤️ ❤️
13/06/23