[tex]3x^{2}+x-10 =0\\\\\Delta = b^{2}-4ac\\\Delta = 1^{2}-4*3*(-10)\\\Delta = 1 + 120\\\Delta = 121\\\\x = \frac{-b\pm\sqrt{\Delta}}{2a}\\ \\x = \frac{-1\pm\sqrt{121}}{2*3} \\\\x = \frac{-1\pm11}{6}\\ \\x'=\frac{-1+11}{6}=\frac{10}{6}=\frac{5}{3} \\\\x"\frac{-1-11}{6}=\frac{-12}{6}=-2[/tex]

S = {-2; 5/3}

Boa noite =)

[tex]\frak{Scorpionatico}[/tex]