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brendinha1217
@brendinha1217
October 2020
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Determine o domínio da seguinte função :
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Heberwagner
F(x) = x² - 6x + 9. Para f(x) = 0, temos:
x² - 6x + 9 = 0, p/ a = 1, b = -6 e c = 9
Δ = (-6)² - 4(1)(9)
Δ = 36 - 36 = 0 => Δ = 0, terá uma raiz real, logo:
x' = x" = [-(-6) + √0]/2.1 = 6/2 = 3
D = {x ∈ IR / x = 3}
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Lista de comentários
x² - 6x + 9 = 0, p/ a = 1, b = -6 e c = 9
Δ = (-6)² - 4(1)(9)
Δ = 36 - 36 = 0 => Δ = 0, terá uma raiz real, logo:
x' = x" = [-(-6) + √0]/2.1 = 6/2 = 3
D = {x ∈ IR / x = 3}