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gabibertini
@gabibertini
July 2022
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Determine o polígno de 54 diagonais.
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jpgp
é um polígono de 12 lados
d= n(n-3)/2
54 =( n² -3n) / 2
54x2 =n² -3n
108 = n² -3n
-n² + 3n + 108 = 0
n² - 3n - 108
delta dá 441 e x = 12
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d= n(n-3)/2
54 =( n² -3n) / 2
54x2 =n² -3n
108 = n² -3n
-n² + 3n + 108 = 0
n² - 3n - 108
delta dá 441 e x = 12