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dedimayer
@dedimayer
October 2020
2
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Determine o valor de x.y
x: [(-1)³-(-1)⁵·(-1)⁴
] +(-1)
⁷
y: (-2)⁴÷2³-4²÷(-2)₂
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eluciamonteiro
Verified answer
x: [(-1)³-(-1)⁵·(-1)⁴] +(-1)⁷
[(-1) - (-1) .(+1)] + (-1)
[-1 - (-1)] - 1
[- 1+ 1]- 1
-1 + 1 - 1
- 1 - 1 + 1
- 2 + 1
- 1
y: (-2)⁴÷2³-4²÷(-2)₂
(+16)
÷ 8 - 16 ÷ (+4)
2 - 4
- 2
Valor de x.y:
x.y
(-1).(-2)
+ 2
15 votes
Thanks 23
roni1
X
= {(-1)^3 -(1)^5 . (-1)^4} + (-1)^7
x = {(-1) - (-1) . (-1) } + (-1)
x = -1 -(-1)-1=-1+1-1= -1
x = -1
y = (-2)^4 : 2^3 - 4^2 : (-2)^2
y = {(-1) . (2)}^4 : 2^3 - 4^2 : (-1)^2 . 2^2
y = {(-1)^4 . (2)^4} : 2^3 - 4^2 : (-1)^2 . 2^2
y = {1 . 16} : 8 -16 : (1 . 4)
y = {16 : 8} - {16 : 4}
y = 2 - 4
y = -2
x . y =
(-1) . (-2) = 2
x . y = 2
6 votes
Thanks 14
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Verified answer
x: [(-1)³-(-1)⁵·(-1)⁴] +(-1)⁷[(-1) - (-1) .(+1)] + (-1)
[-1 - (-1)] - 1
[- 1+ 1]- 1
-1 + 1 - 1
- 1 - 1 + 1
- 2 + 1
- 1
y: (-2)⁴÷2³-4²÷(-2)₂
(+16) ÷ 8 - 16 ÷ (+4)
2 - 4
- 2
Valor de x.y:
x.y
(-1).(-2)
+ 2
x = {(-1) - (-1) . (-1) } + (-1)
x = -1 -(-1)-1=-1+1-1= -1
x = -1
y = (-2)^4 : 2^3 - 4^2 : (-2)^2
y = {(-1) . (2)}^4 : 2^3 - 4^2 : (-1)^2 . 2^2
y = {(-1)^4 . (2)^4} : 2^3 - 4^2 : (-1)^2 . 2^2
y = {1 . 16} : 8 -16 : (1 . 4)
y = {16 : 8} - {16 : 4}
y = 2 - 4
y = -2
x . y =
(-1) . (-2) = 2
x . y = 2