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Arumiaki
@Arumiaki
April 2019
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Determiner les dimensions du tapis Abcd sachant que les coordonnées de A (4 ; 5) B (2 ; 13) C (6 ; 14) D ( 7 ; 6)
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nutella62
Longueur :
BD = √(xD-xB)²+(yD-yB)² = √(7-2)²+(6-13)² = √5²+(-7)² = √25+49 = √74 = 8.6
Largeur :
AB = √(xB-xA)²+(yB-yA)² = √(2-4)²+(13-5)² = √(-2)²+8² = √4+64 =
√68 = 8.25
J'espère t'avoir aidé !
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Un tout petit exo a faire pour demain svp ! (C'est celui du bas)
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Un tout petit exo de maths svp pour demain !
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Effectuer les calculs suivants : A = 3/5 + 6/5 ?B = 5/12 + 4/3 ?C = 5/18 + 1/12 ?D = 3/5 - 6/5 ?E = 7/4 - ( - 3/12) ?F = - 4/3 - 3/5 ?Merci de votre aide !
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BD = √(xD-xB)²+(yD-yB)² = √(7-2)²+(6-13)² = √5²+(-7)² = √25+49 = √74 = 8.6
Largeur :
AB = √(xB-xA)²+(yB-yA)² = √(2-4)²+(13-5)² = √(-2)²+8² = √4+64 = √68 = 8.25
J'espère t'avoir aidé !