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mboumicathia
@mboumicathia
June 2021
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developper (1·√2)²
ecrire sous la forme α√Ь √63+2√28·2√175
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nonotata
(1-V2)² = 1² - 2( 1xV2) + (-V2)² = 1 -2V2 +2 = -2V2 +3
V63+2V28-2V175 = V9x7 +2V4x7 - 2V25x7 = V3²x7 +2V2²x7 -2V5²x7 = 3V7+4V7-10V7 = 7V7-10V7 = -3V7
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June 2021 | 0 Respostas
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June 2021 | 0 Respostas
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V63+2V28-2V175 = V9x7 +2V4x7 - 2V25x7 = V3²x7 +2V2²x7 -2V5²x7 = 3V7+4V7-10V7 = 7V7-10V7 = -3V7