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Manolo17
@Manolo17
April 2019
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Développer :
B = (x - 1)(x - 1) - (x - 2)(x - 3)
Merci de l'aide :)
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B = (x - 1)(x - 1) - (x-2)(x-3) = x² - x - x + 1 - (x² - 3x - 2x - 6) = x² - 2x + 1 - x² + 3x + 2x + 6 = x² - x² - 2x + 5x + 1 + 6 = 3x + 7
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B = (x - 1)(x - 1) - (x-2)(x-3) = x² - x - x + 1 - (x² - 3x - 2x - 6) = x² - 2x + 1 - x² + 3x + 2x + 6 = x² - x² - 2x + 5x + 1 + 6 = 3x + 7