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Mademoiselle3
@Mademoiselle3
April 2019
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Développer et réduire
(2x+5)(-x+2)-(x-3)(-3x+4)
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maudmarine
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Développer et réduire
:
(2x + 5) (- x + 2) - (x - 3) (- 3x + 4)
(-2x² + 4x - 5x + 10) - (-3x² + 4x + 9x - 12)
- 2x² + 4x - 5x + 10 + 3x² - 4x - 9x + 12
- 2x² + 3x² + 4x - 5x - 4x - 9x + 10 + 12
x² - 14x + 22
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bouki83
Développer et réduire:
(2x+5)(-x+2)-(x-3)(-3x+4)
(2x+5)(-x+2)-(x-3)(-3x+4)=(-2x²+4x-5x+10)-(-3x²+4x+9x-12)
=-2x²-x+10 +3x²-4x-9x+12
=x²-14x+22
tu utilises la double distributivité et tu enlèves les parenthèses en respectant les règles des signes.
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Verified answer
Développer et réduire :(2x + 5) (- x + 2) - (x - 3) (- 3x + 4)
(-2x² + 4x - 5x + 10) - (-3x² + 4x + 9x - 12)
- 2x² + 4x - 5x + 10 + 3x² - 4x - 9x + 12
- 2x² + 3x² + 4x - 5x - 4x - 9x + 10 + 12
x² - 14x + 22
(2x+5)(-x+2)-(x-3)(-3x+4)
(2x+5)(-x+2)-(x-3)(-3x+4)=(-2x²+4x-5x+10)-(-3x²+4x+9x-12)
=-2x²-x+10 +3x²-4x-9x+12
=x²-14x+22
tu utilises la double distributivité et tu enlèves les parenthèses en respectant les règles des signes.